Molecular Thermodynamcs of Fluid Phase Equilibria: Solutions by John Prausnitz, Rudiger Lichtenthaler, Edmundo Gomes De

By John Prausnitz, Rudiger Lichtenthaler, Edmundo Gomes De Azevedo

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95 was correct. Using the virial equation, the as- Driving force = (PC3  PC*3 ) 7. 00  1095 . 23 cm3 mol-1 Bmixt v B 1  mixt v 524 cm3 mol-1 , z mixt 10067 . 9845 LM (60) u (50) OP . 70 and y2 x2 D 2,1 8. 2131 . 035. 00268], y1M1P x1H1,2 60 Solutions Manual x 2 J 2 P2s M s2 y2 M 2 P Because x2 = 1, assume J 2 1 . 0401) (8314 . 00255 and x1 This calculation is important to determine solvent losses in natural gas absorbers using methanol as solvent. 9. 2(monomer) dimer The equilibrium constant is Ka ad fd / fd0 (am )2 ( fm / fm0 )2 2 fd §¨ fm0 fm2 ¨© fd0 · ¸ ¸ ¹ where ad is the activity of the dimer, and am is the activity of the monomer.

460 cm3 mol 1 BCO2 BCO2  H2 321 . 01 at equilibrium, CO2 precipitates. To find out how much, assume solid is pure CO2. Let n be the number of moles of CO2 left in the gas phase. 0066 moles CO2 3. To = 313 K Tf = ? Po = 70 bar Pf = 1 bar V L . Condensation will occur in the outlet if fCO ! fCO 2 2 First it is necessary to find the outlet temperature, assuming no condensation. JouleThomson throttling is an isenthalpic process that may be analyzed for 1 mole of gas through a 3step process: I, III: Isothermal pressure changes.

460 cm3 mol 1 BCO2 BCO2  H2 321 . 01 at equilibrium, CO2 precipitates. To find out how much, assume solid is pure CO2. Let n be the number of moles of CO2 left in the gas phase. 0066 moles CO2 3. To = 313 K Tf = ? Po = 70 bar Pf = 1 bar V L . Condensation will occur in the outlet if fCO ! fCO 2 2 First it is necessary to find the outlet temperature, assuming no condensation. JouleThomson throttling is an isenthalpic process that may be analyzed for 1 mole of gas through a 3step process: I, III: Isothermal pressure changes.

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